siriusmart 6d ago • 100%
That would maybe make sense.
Yeah I think the claim might be true, but still there are probably ways to not hit a UN base of fixed location while carrying out an offensive.
This detail wasn't here this morning, the article is gradually edited as more info surfaced. See the url for the original title.
Their reasonings isn't making the slightest sense at all, so unless the article forgot to mention something entirely, this is rediculous.
all nostalgia aside, arras.io is so much better
siriusmart 2mo ago • 100%
Hint: ::: spoiler spoiler Try out the following tasks before going for the big one
- Draw a circle of radius
a
. - Animate a point on circle
a
, let that be your rotational speed. - Animate a circle rolling horizontally (along the
x
axis) at your rotational speed. - Animate a point on that horizontally rolling circle.
You should now have an idea on how to draw a hypocycloid. :::
Draw a hypocycloid using a graphical calculator (such as Desmos or Geogebra). Your hypocycloid should include - Inner circle of radius `a - Outer circle of radius `b - As time `t` increases the point on the inner circle should trace out the pattern, you can animate the graph using `t`. Below is the link to a Desmos graph: https://www.desmos.com/calculator/vzgog7xqrz
siriusmart 3mo ago • 100%
Hint ::: spoiler spoiler If you are studying the algorithm, you are doing it wrong :::
Solution: https://gmtex.siri.sh/fs/1/School/Extra/Maths/Qotd solutions/2024-08-04_extended-euclid.html ::: spoiler spoiler :::
- Given `n` and `m` are coprime, show that there exist integer `n'` such that `nn' mod m=1`. - The *extended Euclid's algorithm* is given below without proof, which may be useful in your proof. (I'm too lazy to type out the algorithm again, so look at the image yourself)
siriusmart 3mo ago • 100%
Hint:
::: spoiler spoiler
Let x mod y = a
:::
Solution: https://gmtex.siri.sh/fs/1/School/Extra/Maths/Qotd solutions/2024-08-01_multiple-of-modulus.html ::: spoiler spoiler :::
- Prove that `z(x mod y) = (zx) mod (zy)` Be rigorous (trust me bro im gonna daily post trust me bro) EDIT: assume all variables are integers
siriusmart 4mo ago • 100%
Hint: ::: spoiler spoiler The size of a set is the number of possible values that an element can take. :::
::: spoiler spoiler solution: https://gmtex.siri.sh/fs/1/School/Extra/Maths/Qotd solutions/2024-06-30_sizes-of-real-sets.html :::
siriusmart 4mo ago • 100%
Solution: ::: spoiler spoiler https://gmtex.siri.sh/fs/1/School/Extra/Maths/Qotd solutions/2024-06-28_log-base-2-approximation.html :::
I recently started reading TAOCP, in other words you can expect daily posts from me again, because I'll just take some of the cooler questions from there and repost them here.
siriusmart 5mo ago • 25%
because I have never heard of this argument before, ever. most media's stance on politics is "their party bad our party good", but the "all the parties are pretty hypocritical" argument has never been explored properly, because its depressing and nobody likes it.
I'm a Londoner, I used to have this friend (who is *not* a Londoner) we had a huge disagreement on topic unspecified. But after I've watched this video I think I see his viewpoint, which is true. I just don't see it at all because there's such a enormous disconnect between London and the rest of the country. I would recommend you to watch the video as well, some arguments made in the video are slightly misleading, but the general picture is clear and true. https://youtu.be/b5aJ-57_YsQ
siriusmart 5mo ago • 100%
yup thats the intended solution, im not really familiar with taylor series yet, but maybe for a person who knows taylor series would be able to see it right away
siriusmart 5mo ago • 100%
Hint ::: spoiler spoiler The solution I have in mind is related to the Taylor series :::
Hint 2 ::: spoiler spoiler It converges to -ln(2), but why :::
Solution: ::: spoiler spoiler https://gmtex.siri.sh/fs/1/School/Extra/Maths/Qotd solutions/2024-06-02-alternating_harmonic.html :::
S=sum of (-1)^n/n from 1 to infty For why I named the post as so, here's why ::: spoiler spoiler ![](https://lemm.ee/api/v3/image_proxy?url=https%3A%2F%2Flemmy.world%2Fpictrs%2Fimage%2Fef511a32-5099-4ec0-a223-47b3b810c684.png) :::
siriusmart 5mo ago • 100%
i main zathura, but okular is a good one as well
siriusmart 5mo ago • 100%
Here's a rly cool solution from stackexchange, which blows my average geometric solution out of the water
::: spoiler spoiler :::
siriusmart 5mo ago • 100%
I've shown that ln(n/n-1) is always larger than 1/n, so Σln(n/n-1) for all natural number n will be larger than the series 1+1/2+1/3+...
but I don't know how to make sure the sum of all ln(p/p-1) only when p is prime is larger than the provided series
the question is strongly suggesting its divergent, i just dont know how to show it
siriusmart 5mo ago • 97%
i pulled the image from a meme channel, so i dont know if its real or not, but at the same time, this below does look like a legit response
siriusmart 5mo ago • 100%
the background it likely ai generated anyways
(i took the meme off some discord channel, so i dont know how its made)
siriusmart 5mo ago • 100%
Hint: ::: spoiler spoiler It is not a telescoping series :::
Solution: ::: spoiler spoiler https://gmtex.siri.sh/fs/1/School/Extra/Maths/Qotd solutions/2024-05-18_not-a-telescoping-series.html :::
siriusmart 5mo ago • 100%
i thought the "default" counter example is y=|x| lol
siriusmart 5mo ago • 100%
i got the answers, but i dont really know why
::: spoiler spoiler https://gmtex.siri.sh/fs/1/School/Extra/Maths/Challenges solutions/bound-f.html :::
siriusmart 5mo ago • 100%
Solution (starter question): ::: spoiler spoiler :::
Please refer to the main post, if you don't like looking at the image. https://gmtex.siri.sh/fs/1/School/Extra/Maths/Unsolved/1d-gravity.html
For the main question, you are encouraged to share your progress ::: spoiler spoiler
You might be able to solve this with differential equations, or by solving the iterative functions, I dont know :::
siriusmart 5mo ago • 100%
i added the solution to the post, i didnt see the multiplication before someone mentioned it, but yeah if we put it to the power of e it will telescope again, which is clearly the main character of this sub at this point (jk)